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x^2=3072
We move all terms to the left:
x^2-(3072)=0
a = 1; b = 0; c = -3072;
Δ = b2-4ac
Δ = 02-4·1·(-3072)
Δ = 12288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12288}=\sqrt{4096*3}=\sqrt{4096}*\sqrt{3}=64\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{3}}{2*1}=\frac{0-64\sqrt{3}}{2} =-\frac{64\sqrt{3}}{2} =-32\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{3}}{2*1}=\frac{0+64\sqrt{3}}{2} =\frac{64\sqrt{3}}{2} =32\sqrt{3} $
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